We might translate the above statement as "~(P→Q)". This WFF of course entails P, and it also entails ~Q. In other words, according to the translation the speaker is in fact saying that Tom is a philosopher and that Tom is not clever. However, in ordinary conversation a person who utters the English statement above might intend no such thing. He might simply be saying that even if Tom is a philosopher, it does not follow that he must be clever. Such a speaker might not in fact know whether Tom is a philosopher, nor might he know whether Tom is clever.
So this example shows that the usual truth-table associated with "if __ then ___" does not capture its correct meaning (given that negation is the correct translation for "it is not the case that").
| P | $P |
| T | T |
| F | F |
| P | $P |
| T | T |
| F | ? |
Since it is given that "(P∨Q)" entails "(P#Q)", "#" cannot have the same truth-table as "→".
(Part b) T. Hint : What is the truth-value of an inconsistent WFF?
If everyone is thinking alike, then somebody isn't thinking.

George Smith Patton